jquery chained dropdown, ga jalan saat di hosting?

Assalamualaikum, permisi para mastah ane mau bertanya kenapa ya ane ada menu dropdown chained menggunakan jquery pas di localhost lancar langsung muncul, nah pas ane upload ke hosting ko malah ngga jalan ya?

apa ada yg kurang dengan kodingan ane? yg otomatis keluar itu yg select paling bawah

<?php
include('sesi-pegawai.php');
$sesi= $_SESSION['pegawai'];
$nip = $_SESSION['nip'];
$nama = $_SESSION['nama'];
?>
<link rel="stylesheet" href="../penilai/f/css/font-awesome.min.css">
<link rel="stylesheet" type="text/css" href="style.css">
<title>Cetak Penilaian</title>
<header>
<div class="user"><i>Selamat Datang Pegawai </i><u>"<? echo $nama?>"</u> <a href="logout.php" ><button class="fa fa-arrow-circle-o-left">Logout</button></a></div>
  <input type="checkbox" id="tag-menu" checked/>
  <label class="fa fa-bars menu-bar" for="tag-menu"></label>
  <div class="jw-drawer">
    <nav>
      <ul>
        <li><a href="index.php"><i><img src="../penilai/images/logo.png" height="140" width="110" align="center"></i></a></li>
        <li><a href="index.php"><i class="fa fa-home"></i>  Home</a></li>
        <li><a href="select.php"><i class="fa fa-bookmark-o"></i>  SKP</a></li>
        <li><a href="select1.php"><i class="fa fa-handshake-o "></i>  Perilaku Kerja</a></li>
        <li><a href="select2.php"><i class="fa fa-check"></i>  Cetak Hasil</a></li>
        <li><a href="user.php"><i class="fa fa-user"></i>  Data Pegawai</a></li>
      </ul>
    </nav>
  </div>
</header>

<div class="content">
 <form method="GET" action="penilaian.php">
Pilih Atasan Penilai : <select name="atasan">
<option value="" disabled="disabled">--Please Select--</option>
 <?php
 $now = date('Y');
 $penilai = $_GET['penilai'];
 $dinilai = $_GET['dinilai'];
 $tahun = $_GET['tahun'];
 $host = "";
 $user = "";
 $pass = "";
 $name = "";
 $link = mysql_connect($host,$user,$pass);
 $pilihdatabase = mysql_select_db($name,$link);
 $a="SELECT * FROM pegawai ORDER by nama asc";
 $sql=mysql_query($a);
 while($data=mysql_fetch_array($sql)){
 ?>
 <option value="<?php echo $data['nip'] ?>"><?php echo $data['nama']?></option>
 <?php
 }
 ?>
 </select>
 <br><br>
 Pilih Penilai : <select name="penilai">
<option value="" disabled="disabled">--informasi--</option>
 <?php
 $a="SELECT * FROM pegawai ORDER by nama asc";
 $sql=mysql_query($a);
 while($data=mysql_fetch_array($sql)){
 ?>
 <option value="<?php echo $data['nip'] ?>"><?php echo $data['nama']?></option>
 <?php
 }
 ?>
 </select><br><br>
Pilih Pegawai yang Dinilai : <select id="dinilai" name="dinilai">
<option value="" disabled="disabled">Please Select</option>
    <?php
        $query = mysql_query("SELECT * FROM pegawai ORDER by nama asc");
         while ($row = mysql_fetch_array($query)) {
    ?>
    <option value="<?php echo $row['nip']; ?>">
    <?php echo $row['nama']; ?>
    </option>
    <?php
       }
       ?>
</select><br><br>
Pilih Tahun : <select id="tahun" name="tahun">
   <option value="" disabled="disabled">Please Select</option>
   <?php
      $query = mysql_query("SELECT * FROM perilaku INNER JOIN pegawai ON perilaku.dinilai = pegawai.nip GROUP BY tahun");
      while ($row = mysql_fetch_array($query)) {
    ?>
    <option id="tahun" class="<?php echo $row['nip']; ?>" value="<?php echo $row['tahun']; ?>">
    <?php echo $row['tahun']; ?>
    </option>
    <?php
    }
    ?>
</select><BR><br>

        <script src="jquery-1.10.2.min.js"></script>
        <script src="jquery.chained.min.js"></script>
        <script>
            $("#tahun").chained("#dinilai");
        </script>

 <input class="button" type="submit" value="Oke"/>
 </form>
</div>