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Warning: mysql_fetch_array(): supplied argument is not a valid
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$sqlk=mysql_query("select * from konfirmasi,pemesanan,barang where pemesanan.idpsn=konfirmasi.idpsn and konfirmasi.idbrg=barang.idbrg and konfirmasi.idmember=pemesanan.idmember");
while($k=mysql_fetch_array($sqlk)){
$sqlm = mysql_query("select * from member where idmember='$rmember[idmember]' ");
$m=mysql_fetch_array($sqlm);
$sqlp = mysql_query("select * from pemesanan where idpsn='$k[idpsn]'");
$pesan=mysql_fetch_array($sqlp);
$sqlb = mysql_query("select * from barang where idbrg='$barang[idbrg]'");
$b=mysql_fetch_array($sqlb);
$i++;
mohon bantuan nya masster2);
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1 Jawaban:
Byk gan salahny terutama di querynya , mending agan belajar dulu database proceduralny
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